x^2+2xy+y^2+3x-3y+4=0

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Solution for x^2+2xy+y^2+3x-3y+4=0 equation: 


Simplifying
x2 + 2xy + y2 + 3x + -3y + 4 = 0

Reorder the terms:
4 + 3x + 2xy + x2 + -3y + y2 = 0

Solving
4 + 3x + 2xy + x2 + -3y + y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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